We can determine the volume of a solid with similar cross-sections using definite integrals. In this post, let's explore how it expands the approximate solution.
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Finding the volume of a solid by integration is another critical integration application. This post explains the theory behind it. At the end of this post, we'll be able to find the volume of an object with a constant cross-section, no matter how complicated it may be.

Approximation

Volume of a solid by approximation

Let's say you're finding the volume \(V\) of the solid figure shown. The object consists of a uniform cross-section throughout its whole length. We can find \(V\) using solid geometry if it is an elementary geometric figure. For unusual solids, the best we can do is approximate them. 

We must divide the solid into multiple parts to estimate the total volume. To do that, imagine the solid as a series of plane sections stacked on each other.

A similar illustration would be a paper ream. That one rectangular ream object consists of multiple sheets of paper. That is how we view the solid - layers making up the 3D object.

Another critical thing to note is that the plane sections that make up the solid must be similar. In our ream example, the cross sections must be rectangular only.

From this, we begin the process of approximating by:

  1. First, divide the 3D object into multiple regular solids. It could be cubes, prisms, cylinders, or any other figure.
  2. Then, we solve the volume \(V\) of each divided solid. From Cavalieri's theorem, \(V=Ah\) where \(A\) is the uniform cross-sectional area and \(h\) is the length of the solid
  3. Finally, we add all individual \(V\) to get the total approximate volume.

Since this is an approximation, how can we have a more accurate answer? We increase the number of divisions \(n\). 

  • When we increase the number of solid divisions, the more closely it would lead to the actual value. 
  • As the number of solids increases, the smaller its volume \(dV\) and height \(h\) become.
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Exact Solution

Exact solution for volume of solid

From the approximate solution, we know that if we want an exact answer, the volume and height of its divisions must be tiny. Building from this, we can solve the precise volume. We will only need to modify two things in the approximate solution: 

  • We need to set up a solid division that is so small we can express its volume as the differential \(dV\)
  • We need an operation that will sum up all of these tiny divisions

We can combine all \(dV\) through integration; hence, the general equation to solve for the volume \(V_T\) with constant cross-section is:

\(V_T=\int_{a}^{b}{dV}\)

  • \(V_T\) is the total volume
  • \(dV\) is the differential volume of the division.
  • \(a\) is the lower limit position (endpoint with the lowest value)
  • \(b\) is the upper limit position (endpoint with the highest value)

This equation is the general expression we use to solve the volume of a 3D object. We can use this as long as the solid obeys Cavalieri's theorem. One critical requirement is that the solid must have a uniform cross-section throughout its length.

We will see this equation a lot, especially in finding the volume of solids of revolutions.

Differential Solid

The differential solid

Let's move on and expound on the differential solid with volume \(dV\). We can express it as \(dV=A \cdot dh\)

  • \(A\) is the cross-sectional area of the solid
  • \(dh\) is the differential thickness

Let's expound more on these variables:

  • The cross-sectional area is a function. We need to express it in terms of the differential variable. The area function will depend on the orientation of the solid if it is along the x, y, or z-axis.
  • The differential thickness \(dh\) is the distance between two points; however, because it is so minuscule, we represent it with a position variable \(x\), \(y\), or \(z\). Again, the thickness will also depend on the orientation.

Most importantly, these two variables \(A\) and \(dh\) must be consistent with the differential variable.

Summary

Solving the volume by integration expands on the approximation solution.
The logic is to subdivide the volume needed with multiple solids, solve for the volume of each part, and add all of these volumes.
It is necessary to keep the volume small to increase the accuracy of the solution; hence, we must represent the volume as differential \(dV\).
We can combine all \(dV\) through integration; hence, the general equation to solve for the volume is: \(V_T=\int_{a}^{b}{dV}\).\(V_T\) is the total volume, \(dV\) is the differential volume of the division, \(a\) is the lower limit position (endpoint with the lowest value), and \(b\) is the upper limit position (endpoint with the highest value)
We can expound the differential solid with volume \(dV\) with Cavalieri's theorem: \(dV=A \cdot dh\). \(A\) is the cross-sectional area of the solid, and \(dh\) is the differential thickness
The cross-sectional area is a function. The area function will depend on the orientation of the solid if it is along the x, y, or z-axis.
The differential thickness \(dh\) is the distance between two points; however, because it is so minuscule, we represent it with a position variable \(x\), \(y\), or \(z\) which will depend on the orientation.
These two variables \(A\) and \(dh\) must be consistent with the differential variable.

Created On
June 5, 2023
Updated On
February 23, 2024
Contributors
Edgar Christian Dirige
Founder
References

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